4x^2-31x+60=0

Solution for 4x^2-31x+60=0 equation:

4x^2-31x+60=0

a = 4; b = -31; c = +60;
Δ = b2-4ac
Δ = -312-4·4·60
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-1}{2*4}=\frac{30}{8}
=3+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+1}{2*4}=\frac{32}{8}
=4
$